8k^2+10k+2=0

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Solution for 8k^2+10k+2=0 equation: 



8k^2+10k+2=0

a = 8; b = 10; c = +2;
Δ = b2-4ac
Δ = 102-4·8·2
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-6}{2*8}=\frac{-16}{16}
=-1
$


$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+6}{2*8}=\frac{-4}{16}
=-1/4
$

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